Last updated at Sept. 3, 2021 by Teachoo
Transcript
Ex 9.4, 6 Find the sum to n terms of the series 3 8 + 6 11 + 9 14 + Step 1: Finding nth term an an = (nth term of 3, 6, 9 ) (nth term of 8, 11, 14, ) an = (3n)(3n + 5) = 9n2 + 15n Step 2: Finding sum of n terms = 9 (n(n+1)(2n+1))/6 +15 (n(n+1))/2 = 9 ( + 1)(2 + 1)/6 + (15 ( + 1))/2 = (3n(n+1)(2n+1))/2 + (15n(n+1))/2 = (3n(n+1))/2 [(2n+1)+5] = (3n(n+1))/2 [2n+1+5] = (3n(n+1))/2 [2n+6] = 3/2n(n+1) 2(n+3) = 3n(n + 1)(n + 3) Hence, The required sum is 3n(n + 1)(n + 3)
Ex 9.4
Ex 9.4, 2 Important Deleted for CBSE Board 2022 Exams
Ex 9.4, 3 Deleted for CBSE Board 2022 Exams
Ex 9.4.4 Important Deleted for CBSE Board 2022 Exams
Ex 9.4, 5 Deleted for CBSE Board 2022 Exams
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Ex 9.4, 7 Important Deleted for CBSE Board 2022 Exams
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Ex 9.4
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